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Math Help - even function

  1. #1
    Junior Member
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    even function

    I have two problems that I cannot get 100% correct! bah! let f(x)= x^2+sin(x). what is g(x) when you shift f(x) to the right 4 and up 7.

    I got this: ((x-4)^2)+sin(x)+7
    but the computer says it isnt right!

    Second, I have to define these next graphs as Even, odd, or neither. and i swear I am getting them right, and if I'm not, could someone please explain?

    sin^2x= neither
    sin(x)^2= even
    sin(cos(x))= odd
    sin(sin(x))= even
    sin(x)+cos(x)= odd

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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by MathNeedy18 View Post
    sin^2x= neither
    [\sin(-x)]^2=[-\sin(x)]^2=[\sin(x)]^2

    sin(x)^2= even
    sin(cos(x))= odd
    <br />
\sin(\cos(-x))=\sin(\cos(x))<br />

    sin(sin(x))= even
    <br />
\sin(\sin(-x))=\sin(-\sin(x))=-\sin(\sin(x))<br />

    sin(x)+cos(x)= odd

    <br />
\sin(-x)+\cos(-x)=-\sin(x)+\cos(x)<br />

    RonL
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  3. #3
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    Hello, MathNeedy18!

    Let: . f(x)\:= \:x^2 + \sin(x).
    What is g(x) when you shift f(x) to the right 4 and up 7?

    I got this: . (x-4)^2+ \sin(x)+7
    . . but the computer says it isn't right! . . . . It isn't
    \text{To shift the graph 4 units to the right,}
    . . \text{replace }{\color{blue}all}\text{ the }x\text{'s with }(x-4).

    You should have had: . g(x)\;=\;(x-4)^2 + \sin(x-4) + 7

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