The problem to find the inverse of a function of the type...
... today has been analysed here...
http://www.mathhelpforum.com/math-he...on-188961.html
Kind regards
The question asks me to find the inverse of a function and find inverse of (3) and f(inverse of 2)
f(t)=t^5 + t^3 + t
I tried going by the steps, but it seemed weird.
y=t^5 + t^3 + t
t=y^5 + y^3 + y
So inverse of f(t) = t^5 + t^3 + t since I can't simplify if any further?
Then for inverse of (3), it would be 3^5 + 3^3 + 3 = 273?
For f(inverse of 2), it would be f(2^5 + 2^3 + 2) = f(42) = 42^5 + 42^3 + 42? Woah...but that seems kind of high...
PLEASE HELP
The problem to find the inverse of a function of the type...
... today has been analysed here...
http://www.mathhelpforum.com/math-he...on-188961.html
Kind regards
I don't think you need the inverse function per se to answer the two questions,
for , , so
for
you may need to solve this w/ a calculator ... say you get , then
edit: Since I've discovered that this post was originally in the calculus forum, I have to ask ... was this a calculus problem looking for the value of a derivative for an inverse function?