The question asks me to find the inverse of a function and find inverse of (3) and f(inverse of 2)
f(t)=t^5 + t^3 + t
I tried going by the steps, but it seemed weird.
y=t^5 + t^3 + t
t=y^5 + y^3 + y
So inverse of f(t) = t^5 + t^3 + t since I can't simplify if any further?
Then for inverse of (3), it would be 3^5 + 3^3 + 3 = 273?
For f(inverse of 2), it would be f(2^5 + 2^3 + 2) = f(42) = 42^5 + 42^3 + 42? Woah...but that seems kind of high...