Notice that multiplying by 1.02 is the same as growing by 2%.
Are my answers correct?
Let R(t) = 55(1.02)t (1.02 to the t power not times t) describe the size of the rabbit population in the PEA woods t days after the first of June. Use your calculator to make a graph of this function inside the window −50 ≤ t ≤ 100, 0 ≤ R(t) ≤ 500. (You will need to work with the variables x and y instead of t and R, of course.) What is the y-intercept of the graph, and what does it signify? Does your calculator show an x-intercept? Would it show an x-intercept if the window were enlarged?
The y intercept is 55 and it stands for the rabbit population on the 1st of June.
This graph will never have an x intercept.
Choose a point on the graph that is very close to the y-intercept, then use these two points to estimate the rate (in rabbits per day) at which the population
is growing on 1 June. In the same way, estimate the rate at which the population is
growing on 1 September. Explain how your two answers are both consistent with the
given 2-percent growth rate.
For the first of June I got a rate of 1 and for the 1 September a rate of 7.
I don't see how these answers are consistent with the 2-percent growth rate.