Need help. And if you could, explain in detail what to do. Here it is:
Determine algebraically whether each of the following functions is even, odd, or neither.
3 = Cubed Root
\| = Square Root
f (x) = 3\|x
I guess it would be hard to read but it's F of X equals the cubed root of X. How would I solve this equation?
Right, Jhevon. I know that much. But what I need help on doing (step by step) is 'testing' or putting it through the process in which we take f(x)=Cubed Root of X and see if it fits the Even, Odd, or Neither profile. Here's one I already know how to do:
f(x) = x / x(squared) - 1
f(-x) = -x / -x(squared) -1 = -x / x(squared) - 1
-f(x) = - x / x(squared) - 1 = - x / x(squared) - 1
And, no, I don't know how to use the /math symbols.
But no, it's not how to get started, it's figuring this certain problem out that's stumping me.
the formulas i gave you tells you the steps. just replace with and simplify. if you get back the original function, then the function is even, if you get the negative of the function, then it is odd. otherwise, it is neither.
example: is even, since
example 2: is odd, since
what is confusing you here? it's the same procedure