Quote Originally Posted by Monkiwrench View Post
You're awesome, Jhevon.

Okay, I have another thing to ask. I want to see how YOU would, step by step, figure out if the following equation would be classified as an even or odd function or neither.

 <br />
f(x) = x^2 - x<br />
Let f(x) = x^2 - x

\Rightarrow f(-x) = (-x)^2 - (-x) = x^2 + x

So f(-x) \ne f(x) and f(-x) \ne -f(x) (which would be x - x^2)

Thus, f(x) is neither even nor odd