Hello, I need help with few questions.

[Solved]

Lim x^2/absolute value of x =0/0

x->0

I don't know how to deal with the absolute value and factoring x^2

Its already in its lowest form therefore i substitute in zero and got the answer.

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[Solved]

If f(x) = -25/2x+3

Find Lim = [f(1+h)-f(1)]/h =0/0

h->0

This is what i had done for Q2:

I substitute in f(x)

= { {-25/[2(1+h)+3]} + [25/(2(1)+3] }/ h

= { [-25/(2h+5)] + (5) } / h

= [ (-25+10h+25)/(2h+5) ] / h

= [ 10h/2h+5 ]/h

= help

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Find c and n

lim [(4)(x^9-11)(x^3+8)] / [(c)(x^n-8)(x^2+17)] = 4/4 = 1

x-> infinity

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let f(x) = [(3)(x^9-12)(x^3+3)] and let g(x) = [(c)(x^n-9)(x^2+16)] with c cannot = 0

Lim

x-> infinity f(x)/g(x)= infinity

Implies that n (greater or equal or less than) (?)

for the last two question i have no idea how to start.

Thank You