$\displaystyle y=\sqrt{x^2-2x}$

I figure the restriction on the domain would be $\displaystyle x\geq2$ or $\displaystyle x\leq0$

$\displaystyle x = \sqrt{y^2-2y}$

$\displaystyle x^2 = y(y-2)$

It's driving me insane. How do I isolate the 'y'?!?

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- Sep 18th 2011, 01:57 PMfreestarFind inverse of a function
$\displaystyle y=\sqrt{x^2-2x}$

I figure the restriction on the domain would be $\displaystyle x\geq2$ or $\displaystyle x\leq0$

$\displaystyle x = \sqrt{y^2-2y}$

$\displaystyle x^2 = y(y-2)$

It's driving me insane. How do I isolate the 'y'?!? - Sep 18th 2011, 02:03 PMTheChazRe: Find inverse of a function
Quadratic formula on y.

y^ - 2y - x^2 = 0

a = 1

b = -2

c = -x^2 - Sep 18th 2011, 02:11 PMskeeterRe: Find inverse of a function
- Sep 18th 2011, 02:52 PMfreestarRe: Find inverse of a function
ahh completing the square. Thanks a lot!

- Sep 18th 2011, 03:04 PMTheChazRe: Find inverse of a function