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Math Help - perpendicular passing through a point

  1. #1
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    perpendicular passing through a point

    the problem is:

    Perpendicuar to y= -5/7x passing through (6/5,0)

    I know that to be perp it has to be opp/co so itll be 7/5x but i dont know what to do next at all.

    The answer says: y= 7/5x - 6/5

    I have no idea how to get there
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  2. #2
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    Re: perpendicular passing through a point

    Quote Originally Posted by gurrry View Post
    the problem is:

    Perpendicuar to y= -5/7x passing through (6/5,0)

    I know that to be perp it has to be opp/co so itll be 7/5x but i dont know what to do next at all.

    The answer says: y= 7/5x - 6/5

    I have no idea how to get there
    The normal will be of the form y = mx + c, and you have already found m = 7/5

    So y = (7/5)x + c

    You also know that (x, y) = (6/5, 0) is a point on the line, so you can use this in the equation of your line

    0 = (7/5) x (6/5) + c

    Solve for c.
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  3. #3
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    Re: perpendicular passing through a point

    Quote Originally Posted by gurrry View Post
    the problem is:
    Perpendicuar to y= -5/7x passing through (6/5,0)
    I know that to be perp it has to be opp/co so itll be 7/5x but i dont know what to do next at all. The answer says: y= 7/5x - 6/5
    You have a point and a slope. Use point-slope form.
    (y-y_0)=m(x-x_0)
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