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Math Help - Parametric equation problem

  1. #1
    Member Veronica1999's Avatar
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    Parametric equation problem

    Could someone take a look at my answers?


    After being thrown from the top of a tall building, a projectile follows a path described parametrically by (x, y) = (48t, 400 − 16t2), where x and y are in feet and t is in seconds.

    (a) How many seconds did it take for the object to reach the ground, where
    y=0? How far from the building did the projectile land?

    (b) How fast was the projectile moving at t = 0 when it was thrown?


    (c) Where was the projectile when t = 2, and (approximately) how fast was it moving?
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  2. #2
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    Re: Parametric equation problem

    Before Being Thrown - Speed is zero (0). This is your answer.
    After Being Thrown - Try that again. Look for linear elements.
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  3. #3
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    Re: Parametric equation problem

    If the ball were thrown with speed 0, it would fall straight down. That does not happen. I do note that the -16t^2 is due to the acceleration of gravity and the 400 is the height of the building so the y- component is that for "falling". But the horizontal position is given by 48t so, for example, it will move 48 feet in one second. What speed is that?
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