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Parametric equation problem

Could someone take a look at my answers?

After being thrown from the top of a tall building, a projectile follows a path described parametrically by (x, y) = (48t, 400 − 16t2), where x and y are in feet and t is in seconds.

(a) How many seconds did it take for the object to reach the ground, where

y=0? How far from the building did the projectile land?

(b) How fast was the projectile moving at t = 0 when it was thrown?

(c) Where was the projectile when t = 2, and (approximately) how fast was it moving?

Re: Parametric equation problem

Before Being Thrown - Speed is zero (0). This is your answer.

After Being Thrown - Try that again. Look for linear elements.

Re: Parametric equation problem

If the ball were thrown with speed 0, it would fall straight down. That does not happen. I do note that the -16t^2 is due to the acceleration of gravity and the 400 is the height of the building so the y- component **is** that for "falling". But the horizontal position is given by 48t so, for example, it will move 48 feet in one second. What speed is that?