1. ## Functions problem

I have the following problem:

My logic is that since I am given one of the values which was divided by, if I multiply by that value I should get the other value.

I tried multiplying (f/g)(x) with f(x) and this is what I did:

I got (x+8) after simplifying the above ^. However, (x+8) does not equal g(x)..

Any help would be greatly appreciated with this problem. Thank you very much in advance (:

2. ## Re: Functions problem

Originally Posted by StaplerPro
I have the following problem:

My logic is that since I am given one of the values which was divided by, if I multiply by that value I should get the other value.

I tried multiplying (f/g)(x) with f(x) and this is what I did:

I got (x+8) after simplifying the above ^. However, (x+8) does not equal g(x)..

Any help would be greatly appreciated with this problem. Thank you very much in advance (:
$\left( {\frac{f}{g}} \right)(x) = \frac{{f(x)}}{{g(x)}} = \frac{{x - 8}}{{x^2 - x}}$

3. ## Re: Functions problem

I'm sorry, I don't fully understand it ):. Could you please explain what "left" means? And how did you get your answer? What does it mean? Sorry for asking so many questions here..

Edit: I understand a bit more now, let me look at what you wrote and reply, ignore what I said up there, thank you (:

4. ## Re: Functions problem

Alright, I used your value and multiplyed it by 1/x and got x^-1 which is also incorrect.. I did my work on paper and can't make sense of what I did @__@. Could you tell me how you got the value that you did, and what my next steps should be please? Thank you very much.

5. ## Re: Functions problem

Look that means that $\frac{\frac{1}{x}}{g}=\frac{x+8}{x^2-x}$

What is $g~?$