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Math Help - Functions problem

  1. #1
    Newbie StaplerPro's Avatar
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    Functions problem

    I have the following problem:
    Functions problem-functionproblem.png

    My logic is that since I am given one of the values which was divided by, if I multiply by that value I should get the other value.

    I tried multiplying (f/g)(x) with f(x) and this is what I did:
    Functions problem-math2b.png
    I got (x+8) after simplifying the above ^. However, (x+8) does not equal g(x)..

    Any help would be greatly appreciated with this problem. Thank you very much in advance (:
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  2. #2
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    Re: Functions problem

    Quote Originally Posted by StaplerPro View Post
    I have the following problem:
    Click image for larger version. 

Name:	functionproblem.png 
Views:	10 
Size:	3.4 KB 
ID:	22243

    My logic is that since I am given one of the values which was divided by, if I multiply by that value I should get the other value.

    I tried multiplying (f/g)(x) with f(x) and this is what I did:
    Click image for larger version. 

Name:	math2b.png 
Views:	6 
Size:	4.8 KB 
ID:	22244
    I got (x+8) after simplifying the above ^. However, (x+8) does not equal g(x)..

    Any help would be greatly appreciated with this problem. Thank you very much in advance (:
    \left( {\frac{f}{g}} \right)(x) = \frac{{f(x)}}{{g(x)}} = \frac{{x - 8}}{{x^2  - x}}
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  3. #3
    Newbie StaplerPro's Avatar
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    Re: Functions problem

    Thank you for your reply, Plato.

    I'm sorry, I don't fully understand it ):. Could you please explain what "left" means? And how did you get your answer? What does it mean? Sorry for asking so many questions here..

    Edit: I understand a bit more now, let me look at what you wrote and reply, ignore what I said up there, thank you (:
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  4. #4
    Newbie StaplerPro's Avatar
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    Re: Functions problem

    Alright, I used your value and multiplyed it by 1/x and got x^-1 which is also incorrect.. I did my work on paper and can't make sense of what I did @__@. Could you tell me how you got the value that you did, and what my next steps should be please? Thank you very much.
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  5. #5
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    Re: Functions problem

    Look that means that \frac{\frac{1}{x}}{g}=\frac{x+8}{x^2-x}

    What is g~?
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