Question about e^2x graph

Use a graph produced by your calculator to estima the values of for which is smaller than . Also, describe clearly and accurately the purpose of each needed step.

This is what I tried but I am totally lost because I can't figure out how to approach this:

I could take the 4th root of both sides but I can't isolate . Not too sure how to solve this question.

Re: Question about e^2x graph

But beside the excercice you need the graphs of the functions, so have you tried to solve this exercice with the calculator? ...

Re: Question about e^2x graph

Try where are the zeros?

Re: Question about e^2x graph

Quote:

Originally Posted by

**freestar** Use a graph produced by your calculator to estima the values of

for which

is smaller than

. Also, describe clearly and accurately the purpose of each needed step.

This is what I tried but I am totally lost because I can't figure out how to approach this:

I could take the 4th root of both sides but I can't isolate

. Not too sure how to solve this question.

It says use a calculator for that reason - plot both graphs on the same axes and pick the appropriate values.

You know that and that the points (0,8^4) and (8,0) lie on it.

You know that has the x-axis as an asymptote and the point (0,1) lies on it.

Here is the wolfram plot, I have limited the domain to make it easier to see: plot {y=e^(2x),y=(x-8)^4} between 0 and 5 - Wolfram|Alpha

Re: Question about e^2x graph

Quote:

Originally Posted by

**e^(i*pi)** It says use a calculator for that reason - plot both graphs on the same axes and pick the appropriate values.

You know that

and that the points (0,8^4) and (8,0) lie on it.

You know that

has the x-axis as an asymptote and the point (0,1) lies on it.

Here is the wolfram plot, I have limited the domain to make it easier to see: http://www.wolframalpha.com/input/?i=plot+{y%3De^%282x%29%2Cy%3D%28x-8%29^4}+between+0+and+5

So in that case, ?

Re: Question about e^2x graph

Re: Question about e^2x graph

Quote:

Originally Posted by

**freestar** So in that case,

?

I'd say so, it agrees with the general value of the plot and I assume your calculator spat it out