In your work, you added -5 to 36 instead of multiplying .....but anyway
I get positive 6 as an answer:
6^3 - 5(6^2)-3(6)-18=0
216-180-36-18=0
So I have this math problem...
is -6 a root of....
x^3-5x^2-3x-18=0? yes or no?
i plug this equation in my calculator and go to the table. It says the coordinates are (-6,0) which means when I plug in -6, it should equal 0... However, when I do the work, I end up getting -183...
(-6)^3-5(-6)^2-3(-6)-18=0
-216 -5 +36 +18 - 18 =0
-216-5+36 = -183 @_@?
am I doing something wrong?
Oh wow...I am one huge dummy.
I checked the coordinates (6,0), not -6. I rechecked and got (-6,-396) ??? Still doesn't make sense..
Plato --
(-6)^3-5(-6)^2-3(-6)-18=0
-216 -5 +36 +18 - 18 =0
-5 is brought down from above and then 36 is the result of -6 squared.
EDIT: Figured out the problem stated above....Thanks! I forgot to multiply 5*36 and instead added them.