Checking a Root of a Cubic

So I have this math problem...

is -6 a root of....

x^3-5x^2-3x-18=0? yes or no?

i plug this equation in my calculator and go to the table. It says the coordinates are (-6,0) which means when I plug in -6, it should equal 0... However, when I do the work, I end up getting -183...

(-6)^3-5(-6)^2-3(-6)-18=0

-216 -5 +36 +18 - 18 =0

-216-5+36 = -183 @_@?

am I doing something wrong?

re: Checking a Root of a Cubic

In your work, you added -5 to 36 instead of multiplying .....but anyway

I get positive 6 as an answer:

6^3 - 5(6^2)-3(6)-18=0

216-180-36-18=0

re: Checking a Root of a Cubic

Quote:

Originally Posted by

**danthegreat** So I have this math problem...

is -6 a root of....

x^3-5x^2-3x-18=0? yes or no?

i plug this equation in my calculator and go to the table. It says the coordinates are (-6,0) which means when I plug in -6, it should equal 0... However, when I do the work, I end up getting -183...

(-6)^3-5(-6)^2-3(-6)-18=0

-216 -5 +36 +18 - 18 =0

-216-5+36 = -183 @_@?

Where did that come from?

re: Checking a Root of a Cubic

Oh wow...I am one huge dummy. (Giggle)

I checked the coordinates (6,0), not -6. I rechecked and got (-6,-396) ??? Still doesn't make sense..

Plato --

(-6)^3-5(-6)^2-3(-6)-18=0

-216 -5 +36 +18 - 18 =0

-5 is brought down from above and then 36 is the result of -6 squared.

EDIT: Figured out the problem stated above....Thanks! I forgot to multiply 5*36 and instead added them.