Given that m=2^x and n=2^y , express (log2)(Squareroot (m^3)n) / 64 in terms of x and y.

So far i got

1/2 (log2)m^3 n - (log2)2^6

1/2 (log2)m^3 n - 6

HELP!~(Doh)

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- Aug 30th 2011, 08:07 AMShapeShifterNeed help with logarithm equation.
Given that m=2^x and n=2^y , express (log2)(Squareroot (m^3)n) / 64 in terms of x and y.

So far i got

1/2 (log2)m^3 n - (log2)2^6

1/2 (log2)m^3 n - 6

HELP!~(Doh) - Aug 30th 2011, 08:17 AMSironRe: Need help with logarithm equation.
I guess the expression is:

What you've done already is fine:

Now use

And afterwards where necessary the definition to simplify:

- Aug 30th 2011, 08:32 AMHallsofIvyRe: Need help with logarithm equation.
- Aug 31st 2011, 12:17 AMShapeShifterRe: Need help with logarithm equation.
yes , the expression is http://latex.codecogs.com/png.latex?...n}}{64}\right)

(log2) 2^3/2x + (log2)2^1/2y - 6

so the answer is (3/2)x + (1/2)y -6

Thanks for helping ! (Clapping) - Aug 31st 2011, 01:20 AMSironRe: Need help with logarithm equation.
You're welcome and enjoy the forum! :)