Find FoGoH. f(x) = tan x, g(x) = x/(x-6) h(x) = x^(1/3) First I did g(h(x)) and I got (x^(2/3) + 6x^(1/3))/(x^(2/3)-36) I'm not really sure where to go from here, and I know I'll be lost as soon as I have to plug my result into tanx. Help?
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Originally Posted by TenaciousE Find FoGoH. f(x) = tan x, g(x) = x/(x-6) h(x) = x^(1/3) First I did g(h(x)) and I got (x^(2/3) + 6x^(1/3))/(x^(2/3)-36)
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