LaTeX on this site.
[tex]|x+2|\le 6 [/tex] gives
Is that so hard to learn?
I'm having issues remembering how to do this.
Ok first of all, I'm not sure how to write absolute value signs on here. And Im also not sure how to write greater/less or equal to inequality signs.
But what I'm trying to figure out is (abs) x + 2 (abs) is greater than or equal to 6.
(and im using the (abs) as the absolute value bars sense i dont know how else to write them)
I know you solve it like this: x+2 greater than or equal to -6, or, x+2 greater than or equal to 6. And you get x is greater than or equal to -8 and x is greater than or equal to 4. So how do i write this in interval notation?
Sorry If ive made it confusing by not being able to properly write this on here.
Good advice! And to start solving it, remember that, without knowing x, we cannot know if |x|= x or |x|= -x. So try both.
Can you solve ? What about ? And for what values of x do those apply?
You could also do a "geometric" solution. Geometrically, we can interpret "|x- y|" as "distance between points x and y". So we can interpret as saying that the points, x, satisfying this are points on the number line whose distance from -2 is greater than or equal to 6. Where are those?