Alright, it goes hand-in-hand with a previous topic titled "Summation Formulas" but yet...it's different at the same time.

This time they give me two series:

1. $\displaystyle 1+1/2+2+5/2+...+6$

2. $\displaystyle [1-(1/2)^2]+[1-(1/3)^2]+[1-(1/4)^2]+...$

My first reaction was that I would have to find the formula myself, where it starts, and where it ends. Simple...except not so much.

The second one ispossibly$\displaystyle \sum_{n=1}^{INF}([1-(1/(1+N)^2])$.

Although that would be way to simple, hehe.

The first one though, I can't seem to find a proper equation that fits the numbers given.