It would be 11 feet above the t-axis?
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Originally Posted by explodingtoenails It would be 11 feet above the t-axis? no. the bottom of the curve (wheel) is y = -19 3 ft below that is the ground at y = -22 now, if you went up 27 ft from the ground, what y-value would you get?
y = 7
Originally Posted by explodingtoenails y = 7 $\displaystyle -22 + 27 \ne 7$ go see your instructor
Oh wow....sorry, I'm really tired. y = 5.......
Now what? D:
Originally Posted by explodingtoenails Now what? D: $\displaystyle -19\cos\left(\frac{2\pi t}{15}\right) = 5$ solve it
t = (arcsin(5/19) + (pi/2))/(2pi/15) t = 4.4 seconds Is that it?
Originally Posted by explodingtoenails t = (arcsin(5/19) + (pi/2))/(2pi/15) t = 4.4 seconds Is that it? that would be the time the seat passes 27 ft above the ground on the way up ... what about on the way down?
10.7 seconds?
Originally Posted by explodingtoenails 10.7 seconds? close ...
Uhm I'm not sure. I just guessed.
Originally Posted by explodingtoenails Uhm I'm not sure. I just guessed. You need to go and see your instructor. Thread closed. CB
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