1. ## Re: Amusement park problem.

It would be 11 feet above the t-axis?

2. ## Re: Amusement park problem.

Originally Posted by explodingtoenails
It would be 11 feet above the t-axis?
no.

the bottom of the curve (wheel) is y = -19

3 ft below that is the ground at y = -22

now, if you went up 27 ft from the ground, what y-value would you get?

y = 7

4. ## Re: Amusement park problem.

Originally Posted by explodingtoenails
y = 7
$-22 + 27 \ne 7$

5. ## Re: Amusement park problem.

Oh wow....sorry, I'm really tired.

y = 5.......

Now what? D:

7. ## Re: Amusement park problem.

Originally Posted by explodingtoenails
Now what? D:
$-19\cos\left(\frac{2\pi t}{15}\right) = 5$

solve it

8. ## Re: Amusement park problem.

t = (arcsin(5/19) + (pi/2))/(2pi/15)

t = 4.4 seconds

Is that it?

9. ## Re: Amusement park problem.

Originally Posted by explodingtoenails
t = (arcsin(5/19) + (pi/2))/(2pi/15)

t = 4.4 seconds

Is that it?
that would be the time the seat passes 27 ft above the ground on the way up ... what about on the way down?

10. ## Re: Amusement park problem.

10.7 seconds?

11. ## Re: Amusement park problem.

Originally Posted by explodingtoenails
10.7 seconds?
close ...

12. ## Re: Amusement park problem.

Uhm I'm not sure. I just guessed.

13. ## Re: Amusement park problem.

Originally Posted by explodingtoenails
Uhm I'm not sure. I just guessed.

CB

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### calculus amusement park problem

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