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Math Help - Amusement park problem.

  1. #31
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    Re: Amusement park problem.

    It would be 11 feet above the t-axis?
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  2. #32
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    Re: Amusement park problem.

    Quote Originally Posted by explodingtoenails View Post
    It would be 11 feet above the t-axis?
    no.

    the bottom of the curve (wheel) is y = -19

    3 ft below that is the ground at y = -22

    now, if you went up 27 ft from the ground, what y-value would you get?
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  3. #33
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    Re: Amusement park problem.

    y = 7
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  4. #34
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    Re: Amusement park problem.

    Quote Originally Posted by explodingtoenails View Post
    y = 7
    -22 + 27 \ne 7

    go see your instructor
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  5. #35
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    Re: Amusement park problem.

    Oh wow....sorry, I'm really tired.

    y = 5.......
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  6. #36
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    Re: Amusement park problem.

    Now what? D:
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  7. #37
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    Re: Amusement park problem.

    Quote Originally Posted by explodingtoenails View Post
    Now what? D:
    -19\cos\left(\frac{2\pi t}{15}\right) = 5

    solve it
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  8. #38
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    Re: Amusement park problem.

    t = (arcsin(5/19) + (pi/2))/(2pi/15)

    t = 4.4 seconds

    Is that it?
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  9. #39
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    Re: Amusement park problem.

    Quote Originally Posted by explodingtoenails View Post
    t = (arcsin(5/19) + (pi/2))/(2pi/15)

    t = 4.4 seconds

    Is that it?
    that would be the time the seat passes 27 ft above the ground on the way up ... what about on the way down?
    Attached Thumbnails Attached Thumbnails Amusement park problem.-ferris4.jpg  
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  10. #40
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    Re: Amusement park problem.

    10.7 seconds?
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  11. #41
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    Re: Amusement park problem.

    Quote Originally Posted by explodingtoenails View Post
    10.7 seconds?
    close ...
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  12. #42
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    Re: Amusement park problem.

    Uhm I'm not sure. I just guessed.
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  13. #43
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    Re: Amusement park problem.

    Quote Originally Posted by explodingtoenails View Post
    Uhm I'm not sure. I just guessed.
    You need to go and see your instructor. Thread closed.

    CB
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