(a+bi)^2=4+4sqrt3i
I got
a^2-b^2+2abi=4+4sqrt3i
a^2=b^2+4
a=sqrt(b^2+4)
2ab=4sqrt3
a=4sqrt3/2b
I can't seem to get the answer when I compare the values
The answer given for a is +/- sqrt 6 and b is +/- sqrt2
I would avoid square roots and start from this. Now so that becomes . Multiply both sides by to get of .
That is a quadratic equation of - and easily factorable. You will find two values for so 4 different values for b.
I can't seem to get the answer when I compare the values
The answer given for a is +/- sqrt 6 and b is +/- sqrt2