Trig and I are not very good friends...

$\displaystyle \displaystyle \frac{1 + tan^2x}{csc^2x} = tan^2x$

This is what I tried:

$\displaystyle \displaystyle \frac{1 + (sin^2x/cos^2x)}{(1/sin^2x)} = tan^2x$

$\displaystyle \displaystyle \frac{cos^2x + sin^2x}{cos^2x} * \frac{sin^2x}{1} = tan^2x$

$\displaystyle (sin^2x)(sin^2x) = tan^2x$

I don't know why it's not equaling up. D: