Hi All,

Bit lost here, tried all sorts of converting but can't quite work it out, just need a push in the right direction.

(lnx)^2-ln(x^3)=10

the square outside the brackets is confusing me.\

Cheers,

Perjac

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- Jul 31st 2011, 02:41 PMperjacA little bit lost with Log solving
Hi All,

Bit lost here, tried all sorts of converting but can't quite work it out, just need a push in the right direction.

(lnx)^2-ln(x^3)=10

the square outside the brackets is confusing me.\

Cheers,

Perjac - Jul 31st 2011, 02:47 PMArchie MeadeRe: A little bit lost with Log solving
- Jul 31st 2011, 03:12 PMPlatoRe: A little bit lost with Log solving
- Jul 31st 2011, 03:30 PMperjacRe: A little bit lost with Log solving
I guess this then becomes an algebra problem (let lnx = a)

a^2 - 3a = 10

though I am not sure how to solve for a. Also is there a link to how to use teh math tags? - Jul 31st 2011, 03:50 PMpickslidesRe: A little bit lost with Log solving
Solve for a using the quadratic formula.

- Jul 31st 2011, 03:52 PMperjacRe: A little bit lost with Log solving
Duh. I shoudl have seen that.

Cheers,

Perjac - Jul 31st 2011, 03:53 PMPlatoRe: A little bit lost with Log solving
I do not believe you there.

If you cannot solve that simple quadratic equation, you have no business trying to solve this question.

As for the use of LaTeX:

Why not learn to post in symbols? You can use LaTeX tags

Example

[tex] a^2-3a=10[/tex] gives $\displaystyle a^2-3a=10$ - Jul 31st 2011, 05:02 PMArchie MeadeRe: A little bit lost with Log solving
- Jul 31st 2011, 05:22 PMperjacRe: A little bit lost with Log solving
- Aug 6th 2011, 08:17 PMnkenjiRe: A little bit lost with Log solving