Hey guys, something that is probably easy for you is lurking below:
We're working on Perpendicular bisectors at the minute, and all my working is perfectly right, but I still seem to be getting the wrong answer. I need to get a hang of it by tomorrow morning (It's currently 10pm) as we are moving on and won't be covering it again.
The exercises which we are using are:
1) Find the equation of the perpendicular bisector of the line joining each pair of points:
A(5, -7) and J (6,4)
I know that I need to get to y-b = m(x-a) and to do this I must first need to figure out the middle point using:
x1+x2 / 2
y1+y2 / 2
Which will fill in a and b of y-b = m(x-a)
I then need to use:
m = y2-y1 / x2-x1
then using the answer to this, I then need to use m1 x m2 = -1 to be able to fill in M in the y-b = m(x-a).
I then need to switch it around so that x + y + n = 0
(where n is number)
But I still seem to be getting the wrong answer. If someone could show me the solution to the above one, I might be able to figure out where I am going wrong.
Also, I have no idea where to start with:
Find the equation of the perpendicular bisector of each side of a triangle with vertices:
P (1, 3), R (0, 4) and Q (5, 2)
Any help would be much appreciated. I think that once I get a grasp of where I am going wrong with the first part, I should be able to figure out the second question.
Thank you so much in advance!