I take an online trig class and every now and again they like to throw in problems we've never seen before, this would be one of those days. An answer would be helpful obviously but if you could also explain how you got it would be great.
The argument of -3a + 4ai is_______ °. Round the answer to one decimal place.
In this case I am breaking a long held principle on my part.Originally Posted by sterces
I am going to give you a complete solution.
WHY? Because I think still using degrees is stupid.
This answer is![\left[ {\pi - \arctan \left( {\frac{4}{3}} \right)} \right]^ \circ](http://latex.codecogs.com/png.latex? \left[ {\pi - \arctan \left( {\frac{4}{3}} \right)} \right]^ \circ )
I think your pi needs to be heated up to 180 degrees .....In this case I am breaking a long held principle on my part.
I am going to give you a complete solution.
WHY? Because I think still using degrees is stupid.
This answer is
The degree operator is applied to entire expression in the brackets.
At least that is the it is done in most CAS.
So thedoes become
.
The reason for that is thatis not in degrees.
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