# Phase shift..

• July 17th 2011, 01:01 PM
JamesBond16
Phase shift..
State the amplitude, period, and phase shift of
U = -1/3 sin(1/2x + pi/4) - 5
• July 17th 2011, 01:11 PM
skeeter
Re: Phase shift..
Quote:

Originally Posted by JamesBond16
State the amplitude, period, and phase shift of
U = -1/3 sin(1/2x + pi/4) - 5

$y = A\sin[B(x+C)] + D$

$A$ ... $|A|$ = amplitude

$B$ ... period, $T = \frac{2\pi}{|B|}$

$C$ ... horizontal or phase shift (+ left , - right)

$D$ ... vertical shift (+ up , - down)

you should be familiar with all of these parameters
• July 17th 2011, 09:18 PM
JamesBond16
Re: Phase shift..
So the period = 1/4 and the phase shift = pi?
• July 18th 2011, 12:45 AM
Siron
Re: Phase shift..
If you wright:
$u=\frac{-1}{3}\sin \left(\frac{x}{2}+\frac{\pi}{4}\right)-5$ as $u=\frac{-1}{3}\sin \left[\frac{1}{2} \left(x+\frac{\pi}{2}\right)\right]-5$

So the period will be: $T=\frac{2\pi}{\frac{1}{2}} = ...$

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