Hi all,
I have the question:
Find an equation of the hyperbola having foci at (-1,1-√52) and (-1,1+√52) and the asymptotes at y=2/3x+5/3 and y=-2/3x+1/3
I know in this equation c^2 = 52 and c = +-√52
I also know the center is (-1,1). I also know by looking at the foci the graph is opening vertically I believe.
I have graphed the asymptotes as well.
I just dont understand how to find A and B. I know it has to do with the slope (2/3) and something with a/b = 2/3 but I have been looking at examples online and I don't understand. From what I've been taught after you find either A or B then you substitute the information into the equation C^2 = A^2 + B^2. Any help would be greatly appreciated thanks