How is it possible to solve this ? Determine values(s) of k for which
1. kx^2 – x – 4 = 0
2. 3x^2 + 5x + k = 0
3. 4x^2 – 3x + k = 0
4. kx^2 + 3x - 7 = 0
5. kx^2 - x - 3 = 0
Thank you
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How is it possible to solve this ? Determine values(s) of k for which
1. kx^2 – x – 4 = 0
2. 3x^2 + 5x + k = 0
3. 4x^2 – 3x + k = 0
4. kx^2 + 3x - 7 = 0
5. kx^2 - x - 3 = 0
Thank you
Hi rcs,Quote:
Originally Posted by rcs
This system is inconsistent. Since,
; which is obviously a contradiction. Hence the system does not have any solution.
Hello, rcs!
Quote:
. .
.
The problem is not clearly stated.
If complex roots are permitted, any value ofcan be used.
If the roots must be real, the discriminant must be nonnegative.
If the roots must be rational, the discriminant must be a square.