Complex Numbers [Equation]

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July 12th 2011, 11:36 AM
Flamuri

Complex Numbers [Equation]

I was solving this equation: $(3 - i)x - 6 = (3+1)x - 4i$
These are my steps:

$(3 - i)x - 6 = (3+i)x - 4i$
$\not{3}\not{x} - ix - 6 = \not{3}\not{x} + ix - 4i$
$4i - 6 = 2ix\begin{cases} & \text{ / } :2i \end{cases}$
$x = \frac{4i}{2i} - \frac{6}{2i}$

$x = 2 - \frac{3}{i}$

But in my teachers book, it's $x = 2+3i$
Can someone help to solve this task? (Shake)

Thanks,
Flamuri
July 12th 2011, 11:51 AM
Plato

Re: Complex Numbers [Equation]

Quote:

Originally Posted by Flamuri

I was solving this equation: $(3 - i)x - 6 = (3+1)x - 4i$
$x = 2 - \frac{3}{i}$
But in my teachers book, it's $x = 2+3i$

That is simple to answer.

$\frac{-3}{i}=3i.$

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