# Thread: One to one functions

1. ## One to one functions

Ok i'm having trouble doing a few problems. The instructions and problem are

*Use the Inverse Function Property to show that f and g are inverses of each other*

1. f(x) = (3 - x) / 4 , g(x) = 3 - 4x

2. f(x) = 1 / x , g(x) = 1 / x

These are only two problems but i'm having trouble figuring it out... help

2. Originally Posted by JonathanEyoon
Ok i'm having trouble doing a few problems. The instructions and problem are

*Use the Inverse Function Property to show that f and g are inverses of each other*

1. f(x) = (3 - x) / 4 , g(x) = 3 - 4x

2. f(x) = 1 / x , g(x) = 1 / x

These are only two problems but i'm having trouble figuring it out... help
You need to show f(g(x)) = x and g(f(x)) = x.

3. Originally Posted by ThePerfectHacker
You need to show f(g(x)) = x and g(f(x)) = x.

How do you do that? Can you show me with #2?

f(x) = 1 / x , g(x) = 1 / x

Thanks I would appreciate it

4. Originally Posted by JonathanEyoon
How do you do that? Can you show me with #2?

f(x) = 1 / x , g(x) = 1 / x

Thanks I would appreciate it
Here we have $f(x) = g(x) = \frac {1}{x}$

Thus, $f(g(x)) = g(f(x)) = \frac {1}{ \frac {1}{x}} = x$

thus, $f(x)$ and $g(x)$ are inverses of each other

5. Originally Posted by Jhevon
Here we have $f(x) = g(x) = \frac {1}{x}$

Thus, $f(g(x)) = g(f(x)) = \frac {1}{ \frac {1}{x}} = x$

thus, $f(x)$ and $g(x)$ are inverses of each other

Ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh !! ok your way is alot simpler to do.

Thanks so much!!