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Math Help - One to one functions

  1. #1
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    One to one functions

    Ok i'm having trouble doing a few problems. The instructions and problem are


    *Use the Inverse Function Property to show that f and g are inverses of each other*

    1. f(x) = (3 - x) / 4 , g(x) = 3 - 4x


    2. f(x) = 1 / x , g(x) = 1 / x




    These are only two problems but i'm having trouble figuring it out... help
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  2. #2
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    Quote Originally Posted by JonathanEyoon View Post
    Ok i'm having trouble doing a few problems. The instructions and problem are


    *Use the Inverse Function Property to show that f and g are inverses of each other*

    1. f(x) = (3 - x) / 4 , g(x) = 3 - 4x


    2. f(x) = 1 / x , g(x) = 1 / x




    These are only two problems but i'm having trouble figuring it out... help
    You need to show f(g(x)) = x and g(f(x)) = x.
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  3. #3
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    Quote Originally Posted by ThePerfectHacker View Post
    You need to show f(g(x)) = x and g(f(x)) = x.


    How do you do that? Can you show me with #2?

    f(x) = 1 / x , g(x) = 1 / x


    Thanks I would appreciate it
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by JonathanEyoon View Post
    How do you do that? Can you show me with #2?

    f(x) = 1 / x , g(x) = 1 / x


    Thanks I would appreciate it
    Here we have f(x) = g(x) = \frac {1}{x}

    Thus, f(g(x)) = g(f(x)) = \frac {1}{ \frac {1}{x}} = x

    thus, f(x) and g(x) are inverses of each other
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  5. #5
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    Quote Originally Posted by Jhevon View Post
    Here we have f(x) = g(x) = \frac {1}{x}

    Thus, f(g(x)) = g(f(x)) = \frac {1}{ \frac {1}{x}} = x

    thus, f(x) and g(x) are inverses of each other



    Ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh !! ok your way is alot simpler to do.

    Thanks so much!!
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