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Math Help - One to one functions

  1. #1
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    One to one functions

    Hello all

    I'm learning one to one functions in class now and i had a few questions that i'm a bit lost in =/

    I have a problem in the book that says to use the Inverse Function property to show that f and g are inverses of each other.


    The first question is

    f(x) = x - 6, g(x) = x + 6

    Well I did two different ways other than using the Inverse Function property

    First I picked a random x value for f using 2. So f(2) = x - 6 which is -4.

    Next I plugged in -4 to g(x) to get -4 + 6 which is 2. So this shows they are inverses.

    The second method I used was, i just found the inverse function of f(x) = x - 6

    y = x - 6

    y + 6 = x

    x + 6 = y which shows it is also inverse. My question is how do i use the Inverse Function property to check? Thanks
    Last edited by JonathanEyoon; September 2nd 2007 at 07:34 AM.
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  2. #2
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    Quote Originally Posted by JonathanEyoon View Post
    Hello all

    I'm learning one to one functions in class now and i had a few questions that i'm a bit lost in =/

    I have a problem in the book that says

    Assume f is a one to one function

    If f(2) = 7, find f^-1(7)
    f^-1(7) means what should x be so that f(x) = 7. In this case it is x=2. Because f(2)=7 like the problem says.

    If f(x) = 5 - 2x, find F^-1(3)
    Do the same thing here. What does x be so that f(x)=3. Meaning 5-2x=3.
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  3. #3
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    Quote Originally Posted by ThePerfectHacker View Post
    f^-1(7) means what should x be so that f(x) = 7. In this case it is x=2. Because f(2)=7 like the problem says.


    Do the same thing here. What does x be so that f(x)=3. Meaning 5-2x=3.

    I managed to figure those out. It was a lot easier than it looked hehe. I appreciate the help!! Think you could help me with my new question? I edited my original post.
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