Thread: Binomial expansion

(1+(1/9)x^2)^-1

How do I begin to expand it? Can I use the expansion of (1+x)^-1 replacing x with (1/9)x^2 ?

I have done it that way. It would be interesting to know if there is another way.

If you wants to apply different method, you can use Maclurin's series expansion

for 1 / (1+x) = 1 - x + x^2 - x^3 + .................