Natural Logs - Homework Question

I haven't taken a math class in over a year and a half and am in A Brief Survey of Calculus right now. Our current lesson is over Natural Logs, but I can't seem to figure out how to do this problem. If someone could please show me how to this it'd be amazing!

5*6^x = 4e^-5x

Re: Natural Logs - Homework Question

What have you tried so far?

Re: Natural Logs - Homework Question

I keep taking the natural log of both sides, which will bring both -5x and x down, then divide -5x by x and the x is cancelled out.

Re: Natural Logs - Homework Question

Ah. Your problem is that the constants on each side of the equation are *not* raised to a power. How does the logarithm handle multiplication? That is, you have

what happens to the 5 on the LHS, and the 4 on the RHS?

Re: Natural Logs - Homework Question

Would you multiply the 5 into the 6? And the 4 into the e? What I end up getting looks like this before I'm lost.

x*ln7.5 = -5x

Re: Natural Logs - Homework Question

Quote:

Originally Posted by

**avonscooper** Would you multiply the 5 into the 6? And the 4 into the e? What I end up getting looks like this before I'm lost.

x*ln7.5 = -5x

No, I don't think you've go the idea yet. What is

Re: Natural Logs - Homework Question

Hello, avonscooper!

Okay, here it is . . .

Take logs: .

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Re: Natural Logs - Homework Question