# sinh(x) and cosh(x)

Yes. To prove it, write $\displaystyle \sinh{x} = \frac{e^x - e^{-x}}{2}$, set it equal to 0 and solve for $\displaystyle x$. Also, set $\displaystyle \cosh{x} = \frac{e^x + e^{-x}}{2}$, and show that this is always positive.