Well, it would have been nice if I'd have beentaughtCramer's Rule, but our lecturer obviously doesn't work that way.

So I've gone away and looked it up, and it seems relatively straight forward with nice values such as x=2 y=1 z=3 from the samples I've seen...

Why don't my equations look like that?!

$\displaystyle V1(20+j48)-j8V2=j4000<0°$

$\displaystyle j20V1-V2(-200-j60)=-j2000<90°$

Pesky j (i) numbers. '<' denotes polar angle.

I think I'll have to break it down so that like terms read straight downwards, so in this case, there will be a 20V1 in equation 1, but there will effectively be 0V1 in equation 2. Is this thinking correct?

Any help will be much appreciated. Thank you in advance.