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Math Help - Graphing linear equation

  1. #1
    Ash
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    Graphing linear equation

    I need help in graphing this equation. Where do you plot a point when you have a fraction as your y-intercept?

    The linear equation is,
    y=1/2x - 3/2

    So, I know, m=1/2 and the y-intercept= (0, -3/2)

    Where do I plot (0,-3/2) on the y-axis and how would that look?
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  2. #2
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    Quote Originally Posted by Ash View Post
    I need help in graphing this equation. Where do you plot a point when you have a fraction as your y-intercept?

    The linear equation is,
    y=1/2x - 3/2

    So, I know, m=1/2 and the y-intercept= (0, -3/2)

    Where do I plot (0,-3/2) on the y-axis and how would that look?
    Hello,

    1. the y-intercept is the point Y(0, -1.5) that means it is situated on the negative y-axis, 1.5 units below the x-axis.

    2. You need a 2nd point to draw the line. Calculate the x-intercept by plugging in y = 0. You'll get the point Z(3, 0).

    3. It isn't necessary to use the axes intercepts. Choose 2 x-values, plug them into the equation and calculate the corresponding y-values. Draw these 2 points and connect them with a straight line:

    x = 1 ===> y = -1
    x = -5 ===> y = -4

    So you have 2 points: A(1, -1) and B(-5, -4) and now you can easily draw the line.
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