I believe I got it. I was taking the angle for B in correctly. It should be 180 - 58 to compensate it for being the Q II. Ill go check the answers to see if im right though
This question might be too trivial for a linear algebra topic but I am not sure what I am doing wrong.
Heres the problem. A is 62.0 an Theta is 58.0 Degrees
I made the triangles and I believe A^y is 29.1 => sin(28) *62.0
A^x is 54.7. => 29.1/tan(28)
for B. B^y is 22.47 => sin(58) * 26.5
B^x is 14.04 => 22.47/tan(58)
C is simply C^y is -31.0
So my equations are
A= 54.7 i + 29.1 j
B= 14.04 i + 22.47 j
C= 0 i - 31.0 j
I wanted to find R^x and R^y and that is simply adding all the related components.
R^x= 68.74
R^y=20.57
I have R^y right but R^x is wrong. Finding the magnitude and angle are easy after that but I am probably getting them wrong from doing R^x wrong. But I keep checking the math and I guess im not seeing something.
Thanks
Edit:
http://imgur.com/ThOBX
Posted a picture of the vectors