Does anyone know how to solve this: 3^y > y^3

I am pretty sure it's y> 3 but i cant prove it.

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- May 30th 2011, 10:37 AM #1

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- May 30th 2011, 11:35 AM #2

The graph of shows that the only interval where is between somewhere near y=2.5 and y=3. It's obvious that the two functions and are equal when y=3. The only way I can see to show that when y>3 is to use calculus (which I guess isn't allowed in the pre-calculus forum). To find the other point where the two functions are equal is definitely tricky – there is no elementary way to find the point where the graph crosses the axis near y=2.5.