I am doing a lot of questions on logarithmic inequality but i am stuck at one question:-

http://i54.tinypic.com/2uo75mb.png

I dont from where to start.

Please help.

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- May 25th 2011, 08:27 PMPranavAroraLogarithmic Inequalities
I am doing a lot of questions on logarithmic inequality but i am stuck at one question:-

http://i54.tinypic.com/2uo75mb.png

I dont from where to start.

Please help. - May 25th 2011, 08:36 PMFernandoRevilla
Use that the inequality $\displaystyle \log_3 y\geq 0$ is equivalent to $\displaystyle y\geq 1$

- May 25th 2011, 09:33 PMPranavArora
- May 25th 2011, 11:08 PMFernandoRevilla
We have $\displaystyle x^2+|x-5|>0$ for all $\displaystyle x\in\mathbb{R}$ so, the inequality is equivalent to $\displaystyle |x^2-4x|+3\geq x^2+|x-5|$ . Now use the definition of the absolute value, $\displaystyle |x-5|=x-5$ if $\displaystyle x>5$ , ... etc.