Hi,
Q) Separate into real and imaginary parts (write as a simple complex number):
- (-2 + 3i)²/(1 + i)
Please help me solving it ! I know the method is by multiplying it with conjugate but can't get a proper answer.
First expand the numerator $\displaystyle (-2+3i)^2 $
$\displaystyle 4+(2)(-2)(3i) + 9i^2 $
$\displaystyle 4-12i+9i^2 $
Since $\displaystyle i^2 = -1 $ then $\displaystyle -5-12i $
Now multiply your new fraction by the conjugate of $\displaystyle (1+i) $ which is $\displaystyle 1-i$