x= -(1+y)
(y-1)^2=4-(1+y)
y^2-2y+1-4+1+y=0
y^2-y-2=0
You continue.
I am trying to solve this system of equations
(y-1)^2=4+x
x+y=-1
This is what I did
y^2-1y-1y-1y+1=4+x
y^2-2y+1=4+x
y^2-2y-3=x
Then I used the quadratic formula to get x=-3
Then plugged that in to x+y=1
I got y=2
Now I am confused because according to my book there are two solutions for this program I found (-3,2)
But I am having trouble finding the other solution?