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Thread: Method of Differences

  1. May 20th 2011, 08:34 PM #1
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    Method of Differences

    Using the method of differences, prove that \sum_{r = 1}^{2n}r^2=\frac{1}{6}n(n+1)(2n+1)
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  2. May 20th 2011, 10:16 PM #2
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    I don't know what the method of differences is, but



    This should also help you to get the required result...

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