I am having difficulty with one more question
y^2+8x=0 rotated on pi/6
I did this
x= cos(pi/6)x+sin(pi/6)y
square root 3 / 2 x+1/2y
For y I got -1/2X+ square root 3/2y
Then I plug it in
(-1/2x+ square root 3/2y)^2+8( square root 3 /2 x +1/2y)
But I am having trouble figuring out the equation.
1. Do yourself (and us) a favour and start a new thread if you have a new question.
2. I assume that the center of rotation is the origin(?). If so you know:
With and
you'll get:
3. Plug in these terms into the original equation which yields:
4. Expand the brackets and collect like terms:
I have a question when you wrote the equation why is it square root of 3 instead of square root of 3 over 2? I mean it makes sense in the final answer.
Also would instead of having 1/2 in the equation would you not have 2 because if you plug it back into the equation with two it makes more sense to me
As I checked and found out the answer to this problem is
x^2-2square root 3 xy +3(y)^2+ 16square root 3 x+16y
And if you use 2 instead of 1/2 in the equation I would get that answer.