Write an equation of the translated or rotated graph in general form.

y=3x^2-2x+5 T(2,-3)

I know the graph is a parabola. But I am not sure where I would "plug in" h and k into this equation. To get the translated equation.

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- May 15th 2011, 08:55 PMhomeylova223Transformations of conics?
Write an equation of the translated or rotated graph in general form.

y=3x^2-2x+5 T(2,-3)

I know the graph is a parabola. But I am not sure where I would "plug in" h and k into this equation. To get the translated equation. - May 16th 2011, 01:47 AMearboth
- May 16th 2011, 04:33 PMhomeylova223
I am having difficulty with one more question

y^2+8x=0 rotated on pi/6

I did this

x= cos(pi/6)x+sin(pi/6)y

square root 3 / 2 x+1/2y

For y I got -1/2X+ square root 3/2y

Then I plug it in

(-1/2x+ square root 3/2y)^2+8( square root 3 /2 x +1/2y)

But I am having trouble figuring out the equation. - May 16th 2011, 11:13 PMearboth
1. Do yourself (and us) a favour and start a new thread if you have a new question.

2. I assume that the center of rotation is the origin(?). If so you know:

With and

you'll get:

3. Plug in these terms into the original equation which yields:

4. Expand the brackets and collect like terms:

- May 17th 2011, 11:29 AMhomeylova223
I have a question when you wrote the equation why is it square root of 3 instead of square root of 3 over 2? I mean it makes sense in the final answer.

Also would instead of having 1/2 in the equation would you not have 2 because if you plug it back into the equation with two it makes more sense to me

As I checked and found out the answer to this problem is

x^2-2square root 3 xy +3(y)^2+ 16square root 3 x+16y

And if you use 2 instead of 1/2 in the equation I would get that answer. - May 17th 2011, 11:48 PMearboth