i must sketch graph of these 2 functions

y=4log4x+1

y=e^3x

I am unsure how to find x and y intercepts for this problems could anyone please show me formula how to get coordinates to make this graph:rolleyes:

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- Aug 26th 2007, 05:11 AMgregoriographing log
i must sketch graph of these 2 functions

y=4log4x+1

y=e^3x

I am unsure how to find x and y intercepts for this problems could anyone please show me formula how to get coordinates to make this graph:rolleyes: - Aug 26th 2007, 05:54 AMred_dog
$\displaystyle f(x)=4\log 4x+1,f:(9,\infty)\to\mathbf{R}$

To find the interecept with x-axis, you must to solve the equation $\displaystyle f(x)=0$.

$\displaystyle \displaystyle 4\log 4x+1=0\Rightarrow \log 4x=-\frac{1}{4}\Rightarrow 4x=10^{-\frac{1}{4}}\Rightarrow x=\frac{1}{4\cdot 10^{\frac{1}{4}}}$

The graph does not intercept y-axis.

$\displaystyle g(x)=e^{3x},g:\mathbf{R}\to(0,\infty)$

The graph does not intercept the x-axis.

To find the intercept with y-axis, you have to calculate $\displaystyle g(0)$:

$\displaystyle g(0)=1$

Then give to $\displaystyle x$ some other values in the domain to find some other values for $\displaystyle f$ or $\displaystyle g$.

Here are the sketches.

http://img513.imageshack.us/img513/6533/graphsnh9.jpg - Aug 26th 2007, 07:22 AMgregorioto substitute into eaquations
so then for completing the plot where do i substitute in equation for making curves ?? thanks