Hint: Where is
Find the exact ans:
modulus: e^{2x} - e^{-2(x-1)} dx
the solution given was to be
\int_{-1}^{0.5} e^{2x} - e^{-2(x-1)} dx + \int_{0.5}^1 {e^{2x}-e^{-2(x-1)} dx
I dont understand why there is a need to do this. Why cant we integrate directly? Why is it 0.5?
Sorry i didnt why Latex couldnt work. i tried a lot of times