4y + 4 = 3x -->

4y - 8 = 3x - 12 .....(we need the left to be a multiple of y - 2, and the right a multiple of x - 4 )

4(y - 2) = 3(x - 4)

y - 2 = 3/4(x - 4)

Now 3/4 is either a/b or b/a, depending on whether this is vertical or horizontal hyperbola (I can't remember which at the moment, so I'll leave it at that).