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Math Help - Finding θ in r=1/32vēsin2θ?

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    Finding θ in r=1/32vēsin2θ?

    I cant figure out this problem:
    "A baseball leaves the hand of the first baseman at an angle of θ with the horizontal and initial velocity of v(subscript 0)=80 feet per second. The ball is caught by the second baseman 100 feet away. Find θ if the range, r, of a projectile is given by r=1/32vē sin2θ. (note: the range is the horizontal distance the ball travels.)
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    Quote Originally Posted by Deo3560 View Post
    I cant figure out this problem:
    "A baseball leaves the hand of the first baseman at an angle of θ with the horizontal and initial velocity of v(subscript 0)=80 feet per second. The ball is caught by the second baseman 100 feet away. Find θ if the range, r, of a projectile is given by r=1/32vē sin2θ. (note: the range is the horizontal distance the ball travels.)

    sub in your given values and solve the equation for 2\theta , then determine \theta ...

    100 = \dfrac{80^2 \sin(2\theta)}{32}
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