# Finding θ in r=1/32v²sin2θ?

• May 8th 2011, 02:47 PM
Deo3560
Finding θ in r=1/32v²sin2θ?
I cant figure out this problem:
"A baseball leaves the hand of the first baseman at an angle of θ with the horizontal and initial velocity of v(subscript 0)=80 feet per second. The ball is caught by the second baseman 100 feet away. Find θ if the range, r, of a projectile is given by r=1/32v² sin2θ. (note: the range is the horizontal distance the ball travels.)
• May 8th 2011, 04:14 PM
skeeter
Quote:

Originally Posted by Deo3560
I cant figure out this problem:
"A baseball leaves the hand of the first baseman at an angle of θ with the horizontal and initial velocity of v(subscript 0)=80 feet per second. The ball is caught by the second baseman 100 feet away. Find θ if the range, r, of a projectile is given by r=1/32v² sin2θ. (note: the range is the horizontal distance the ball travels.)

sub in your given values and solve the equation for $2\theta$ , then determine $\theta$ ...

$100 = \dfrac{80^2 \sin(2\theta)}{32}$