For the equation of each ellipse find the coordinates of the centre,foci, and vertices. 1. 49x^2+16y^2+160y-384=0 (49x^2+0+0)+ 16(y^2+10y+25)= 384+16(25) This is what I did (0x+0)+16(y+5)^2=784 0x/784+(y+5)^2/49 Have I set up the equation right?
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Originally Posted by homeylova223 For the equation of each ellipse find the coordinates of the centre,foci, and vertices. 1. 49x^2+16y^2+160y-384=0 (49x^2+0+0)+ 16(y^2+10y+25)= 384+16(25) This is what I did (0x+0)+16(y+5)^2=784 Where did the 49x^2 go?? -Dan
With 49x^2 I am not sure how to complete the square so I did (0/98)^2=0.
Yes, so it is 49(x^2- 0)= 49x^2- it already is a perfect square. Now divide both sides by 49(16)
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