For the equation of each ellipse find the coordinates of the centre,foci, and vertices.
(49x^2+0+0)+ 16(y^2+10y+25)= 384+16(25) This is what I did
0x/784+(y+5)^2/49 Have I set up the equation right?(Giggle)
Where did the 49x^2 go??
Originally Posted by homeylova223
With 49x^2 I am not sure how to complete the square so I did (0/98)^2=0.
Yes, so it is 49(x^2- 0)= 49x^2- it already is a perfect square.
Now divide both sides by 49(16)